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7=x^2-12x
We move all terms to the left:
7-(x^2-12x)=0
We get rid of parentheses
-x^2+12x+7=0
We add all the numbers together, and all the variables
-1x^2+12x+7=0
a = -1; b = 12; c = +7;
Δ = b2-4ac
Δ = 122-4·(-1)·7
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{43}}{2*-1}=\frac{-12-2\sqrt{43}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{43}}{2*-1}=\frac{-12+2\sqrt{43}}{-2} $
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